The displacement 'x' (in meter) of a particle of mass 'm' (in kg) moving in one dimension under the action of a force is released to time 't' (in sec) by `t = sqrt(x) + 3`. The displacement of the particle when its velocity is zero will be.

Options

A. zero
B. 3 units
C. `sqrt 3 ` units
D. 9 units

Answer

A

Explanation

` x(t) =(t-3)^(2) =t^(2) +9-6t `
` rArr " "v(t) =2t -6 and a (t) =2 " "rArr v(t) =0 ` when t = 3s and x (3) =0