If the velocity of a particle is given by `v=(180-16x)^((1)/(2))(m)/(s)`, then its acceleration will be

Options

A. zero
B. ` 8 m//s^(2) `
C. ` -8m//s ^(2) `
D. ` 4 m//s^(2) `

Answer

C

Explanation

` v^(2) =180 -16x `
Taking derivative w.r.t. X
` 2v (dv)/(dx) =-16 " "rArr a=v (dv)/(dx) =-8m//s^(2) `