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A particle moves along a straight line. ...

A particle moves along a straight line. Its position at any instant is given by `x = 32t-(8t^3)/3` where x is in metres and t in seconds. Find the acceleration of the particle at the instant when particle is at rest.

A

` -16 ms^(-2) `

B

` -32 ms^(-2)`

C

` 32 ms^(-2)`

D

` 16ms ^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B
` x= 32 t -(8t^(3))/(3) rArr " "v= 32 -8t^(2) " "rArr " "v= 0 at t = 2 sec `
` a=- 16 t " "rArr " " at t =2 sec , " "a = -32 m//s^(2) `
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