Home
Class 12
PHYSICS
Statement-1: When velocity of a particle...

Statement-1: When velocity of a particle is zero then acceleration of particle must be zero at that instant
Statement-2: Acceleration is equal to`a= v ((dv)/(dx)) ` , where v is the velocity at that instant .

A

Statement-1 is true, Statement-2 is true, Statement-2 is a correct explanation for Statement-1

B

Statement-1 is true, Statement-2 is true, Statement-2 is not a correct explanation for Statement-1.

C

Statement-1 is true, Statement-2 is false

D

Statement-1 is false, Statement-2 is true

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the statements provided in the question, we will evaluate each statement step by step. ### Step 1: Evaluate Statement 1 **Statement 1:** When the velocity of a particle is zero, then the acceleration of the particle must be zero at that instant. **Analysis:** - This statement is **false**. - To understand why, consider a projectile thrown vertically upward. At the highest point of its trajectory, the velocity of the projectile is indeed zero. However, the acceleration due to gravity is still acting on it, which is approximately -9.81 m/s² (downward). - Therefore, it is possible for a particle to have zero velocity while still experiencing non-zero acceleration. ### Step 2: Evaluate Statement 2 **Statement 2:** Acceleration is equal to \( a = v \left( \frac{dv}{dx} \right) \), where \( v \) is the velocity at that instant. **Analysis:** - This statement is **true**. - The relationship can be derived from the definitions of acceleration and velocity. - Acceleration \( a \) is defined as the rate of change of velocity with respect to time, \( a = \frac{dv}{dt} \). - Velocity \( v \) is defined as the rate of change of position with respect to time, \( v = \frac{dx}{dt} \). - By using the chain rule, we can express acceleration in terms of velocity and position: \[ a = \frac{dv}{dt} = \frac{dv}{dx} \cdot \frac{dx}{dt} = v \left( \frac{dv}{dx} \right) \] - Hence, Statement 2 is correct. ### Conclusion - **Statement 1 is false.** - **Statement 2 is true.** Thus, the correct conclusion is that Statement 1 is false and Statement 2 is true. ### Final Answer The correct option is that Statement 1 is false and Statement 2 is true. ---

To analyze the statements provided in the question, we will evaluate each statement step by step. ### Step 1: Evaluate Statement 1 **Statement 1:** When the velocity of a particle is zero, then the acceleration of the particle must be zero at that instant. **Analysis:** - This statement is **false**. - To understand why, consider a projectile thrown vertically upward. At the highest point of its trajectory, the velocity of the projectile is indeed zero. However, the acceleration due to gravity is still acting on it, which is approximately -9.81 m/s² (downward). ...
Promotional Banner

Similar Questions

Explore conceptually related problems

Statement-I : When velocity of a particle is zero then acceleration of particle is zero. Statement-II : Acceleration is equal to rate of change of velocity.

In a linear S.H.M., the acceleration of the particle is zero, when its velocity is

A : When the velocity of an object is zero at an instant, the acceleration need not be zero at that instant. R : In motion under gravity, the velocity of body is zero at the top - most point.

If the instantaneous velocity of a particle is zero, will its instantaneous acceleration be necessarily zero

Assertion: If velocity of a particle at a certain instant is zero then its acceleration must also be zero at the same instant. Reason: When a particle is projected upward under gravity then at the top point its instantaneous velocity becomes zero.

The velocity of a particle at an instant "t" is v=u+at ,where u is initial velocity and a is constant acceleration.The v -t graph are

If the velocity of the a particle moving on x-axis is given by v=3t^(2)-12 t +6. at what time is the acceleration of particle zero ?

The velocity of a particle moving with constant acceleration at an instant t_(0) is 10m//s After 5 seconds of that instant the velocity of the particle is 20m/s. The velocity at 3 second before t_(0) is:-

A particle moves along the x-axis obeying the equation x=t(t-1)(t-2) , where x is in meter and t is in second a. Find the initial velocity of the particle. b. Find the initial acceleration of the particle. c. Find the time when the displacement of the particle is zero. d. Find the displacement when the velocity of the particle is zero. e. Find the acceleration of the particle when its velocity is zero.