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A body starts moving with a velocity v0 ...

A body starts moving with a velocity `v_0 = 10 ms^-1.` It experiences a retardation equal to `0.2v^2.` Its velocity after 2s is given by

A

` + 2m s^(-1) `

B

` +4 ms ^(-1) `

C

` -2ms^(-1) `

D

` + 6ms^(-1) `

Text Solution

Verified by Experts

The correct Answer is:
A
` a= (dv)/(dt) =-0.2V^(2) rArr int _(v_0) ^(v) (dV)/(V^(2)) =-0.2int _0^(t) dt rArr " "(1)/(V) -(1)/(V_0) =0.2t " "rArr " " at t =2 sec , v= 2 m//s `
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