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The displacement of a particle moving in...

The displacement of a particle moving in a straight line is described by the relation `s=6+12t-2t^(2)`. Here `s` is in metre and `t` in second. The distance covered by the particle in first `5s` is

A

20 m

B

32 m

C

24m

D

26m

Text Solution

Verified by Experts

The correct Answer is:
D
` v= dx //dt =12 - 4t =0 rArr t= 3 sec ." "," "x(0 ) =6,x (3) = 6+36 -18=24 cm `
` rArr `distance covered in first 3 sec is 18m.
Therefore , distance travelled between `t= 3s "to" 5s "is" 8m` So , Total distance travelled is ` 18 +8 =26 m `
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