Two bodies begin to fall freely from the same height but the second falls T second after the first. The time (after which the first body begins to fall) when the distance between the bodies equals L is

Options

A. `(1)/(2) T`
B. ` (T)/(2) +(L) /( gT) `
C. ` (L)/(gT) `
D. ` T+( 2L)/(gT) `

Answer

B

Explanation

` 1^(st) ` body : ` -(x+L) =-(g)/(2) t^(2) `
2nd body :-x `= -(g)/(2) (t-T) ^(2) `
`rArr " "t= (T)/(2) +(L)/( gT) `
` (##VMC_PHY_XI_WOR_BOK_01_C02_E02_074_S01.png" width="80%">