A particle moving with a uniform acceleration along a straight line covers distances `a` and `b` in successive intervals of `p` and `q` second. The acceleration of the particle is

Options

A. ` (pq(p+q))/( 2(dp-aq))`
B. ` (2(aq-dp))/(pq(p-q)) `
C. ` (bp-aq)/(pq(p-q)) `
D. ` (2(bp-aq))/(pq(p+q))`

Answer

D

Explanation

` a =u p +(1)/(2) AP^(2) ……….. ` let u : initial velocity at the beginning of internal seconds . And acc: A
` b=u (p+q) +(1)/(2) A(p+q)^(2) -up -(1)/(2) AP^(2) =uq + (1)/(2) A( q^(2) +2pq ) `
` rArr aq -bp =(1)/(2) A^(2)q- (1)/(2) Ap(q^(2) +2pq) =-(A)/(2) pq(p+q) rArr " "A=(2(bp-aq))/(pq(p+q))`