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From the top of a tower of height 200 m,...

From the top of a tower of height 200 m, a ball A is projected up with speed `10ms^(-1)` and 2 s later, another ball B is projected vertically down with the same speed. Then

A

Both A and B will reach the ground simultaneously

B

Ball A will hit the ground 2s later than B hitting the ground

C

Both the balls will hit the ground with the same velocity

D

Both the balls will hit the ground with different velocity

Text Solution

Verified by Experts

The correct Answer is:
A, C

Ball A will return to the top of tower after ` T=( 2u)/(g) =(2xx 10 )/( 10 ) 2s ` with speed of `10 ms^(-1) ` downward.And this time, B is also projected downwards with ` 10 ms^(-1) ` so both reach ground simultaneously. Also they will hit the ground with the same speed..
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