A body is allowed to fall from a height of `100 m`. If the time taken for the first `50 m` is `t_1` and for the remaining `50 m` is `t_2` then :

Options

A. `t_1 =t_2`
B. ` t_1 gt t_2`
C. ` t_1 lt t_2`
D. Depends upon the mass

Answer

B

Explanation

`S= (1)/(2) g t_1^(2) or t_1^(2) =( 50 xx 2 )/( g) =(100)/(g) or t_1 =(100)/( sqrt g) and 100 =(1)/(2) g t^(2) or t =(10 sqrt2)/(sqrtg)`
` t_2 =t-t_1 =(10)/(sqrtg) (sqrt2-1) =0.4 t_1`