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A particle starts from rest and traverse...

A particle starts from rest and traverses a distance l with uniform acceleration, then moves uniformly over a further distance 2l and finally comes to rest after moving a further distance 3l under uniform retardation. Assuming entire motion to be rectilinear motion the ratio of average speed over the journey to the maximum speed on its ways is

A

` 1//5`

B

` 2//5`

C

` 3//5`

D

` 4//5 `

Text Solution

Verified by Experts

The correct Answer is:
C

Let v: maximum speed
`rArr " "l(1)/(2) vt_1 ,2l =v(t_2-t_1)3l, =(1)/(2) v ( t_3-t_2) `
`rArr t_1=2l//v,t_2=(4l)/(v) ,t_3=10l //v`
`rArr ` av . Velocity `=(l+2l+3l)/(10l//v) =(3v)/(5) rArr ("av.velocity ")/("m.ax.velocity ") =(3)/(5)`
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