Home
Class 12
PHYSICS
Two particles are released from the same...

Two particles are released from the same height at an interval of `1s`. How long aftger the first particle begins to fall will the two particles be `10m` apart? (`g=10m//s^(2)`)

A

1.5 s

B

2 s

C

1.25 s

D

2.5 s

Text Solution

Verified by Experts

The correct Answer is:
A
Let the particles be 10m apart when the first has fallen for t sec
` rArr " " (1)/(2) g t^(2) -(1)/(2) g( t-1)^(2) =10 `
` rArr " "t= 1.5s `
` (##VMC_PHY_XI_WOR_BOK_01_C02_E03_044_S01.png" width="80%">
Promotional Banner

Similar Questions

Explore conceptually related problems

Two diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10 m apart? Take g = 10 m//s^2.

Two bodies begin a free fall from rest from the same height 2 seconds apart. How long after the first body begins to fall, the two bodies will be 40 m apart? ("Take g = 10ms"^(-2))

Two balls are released from the same height at an interval of 2s. When will the separation between the balls be 20m after the first ball is released? Take g=10m//s^(2) .

Two particles begin to fall freely from the same height but the second falls t_(0) second after the first. Find the time (after the dropping of first) when separation between the particles is h_(0) .

Two balls are dropped from the same point after an interval of 1s. If acceleration due to gravity is 10 m//s^(2) , what will be their separation 3 seconds after the release of first ball?

A particle is thrown vertically up from the top of a building of height 20m with initial velocity u. A second particle is released from the same point 1 second later. If both particles reach the ground at the same instant , 3u = m//s. [Take g= 10m//s^(2) ]

Two particles A and B masses 1 kg and 2 kg respectivelty are projected in the same vertical line as shown in figure with speeds u_(A) = 200 m//s and u_(B) = 85m//s respectively. Initially they were 90 m apart. Find the maximum height attained by the centre of mass of the system of particles A and B, from the initial position of centre of mass of the system. Assume that none of these particles collides with the ground in that duration Take g = 10 m//s^(2)

Two balls of equal masses are thrown upwards, along the same vertical direction at an interval of 2 seconds, with the same initial velocity of 40m//s . Then these collide at a height of (Take g=10m//s^(2) ).

Two particles are projected with speed 4m//s and 3m//s simultaneously from same point as shown in the figure. Then:

Two particles are projected with speed 4 m//s and 3 m//s simultaneously from same point as shown in the figure. Then :