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A ball is released from the top of a tow...

A ball is released from the top of a tower of height h metre. It takes T second to reach the ground. What is the position of the ball in `T/3` second?

A

` ((8h))/(9) ` metre from the groud

B

`((7h))/(9) ` metre from the ground

C

`(h)/(9) ` metre from the ground

D

`((17h))/(18) ` metre from the ground

Text Solution

Verified by Experts

The correct Answer is:
A
`h= ut+(1)/(2) gt^(2) rArr h= (1)/(2) g T^(2) `
After ` T//3` seconds the position of ball form
` h=0+(1)/(2) g((T)/(3))^(2) =(1)/(2) xx (g)/( 9)xx T^(2) =(h)/(9) `
` therefore " "` Position of ball from ground `=h-(h)/(9) =(8h)/(9) `
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