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All the graphs below are intended to rep...

All the graphs below are intended to represent the same motion. One of them does it incorrectly. Pick it up.

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
B
If velocity versus time graph is a straight line with negative slope, then acceleration is constant and negative.
With a negative slope distance-time graph will be parabolic ` (s=ut -(1)/(2) at^(2)) ` So option (B) will be incorrect.
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