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(sin 3theta-sin theta sin^2(2theta))/(si...

`(sin 3theta-sin theta sin^2(2theta))/(sin theta+sin 2thetacos theta)=cosx` then `x=`

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(sin3 theta-sin theta * sin ^ (2) (2 theta)) / (sin theta + sin2 theta * cos theta) = cos x rarr x =

sin theta+sin2 theta+sin3 theta=1+cos theta+cos2 theta

Knowledge Check

  • (sin 3 thea - sin theta sin ^(2) (2 theta ))/( sin theta + sin 2 theta cos theta ) = cos x implies x =

    A
    `4 theta `
    B
    `2theta `
    C
    `theta `
    D
    `3 theta `

  • sin^(3)theta + sin theta - sin theta cos^(2)theta =

    A
    0
    B
    `sin theta`
    C
    `sin 2 theta`
    D
    `2sin^(3)theta`

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    (sin theta+2sin3 theta+sin5 theta)/(sin3 theta+2sin5 theta+sin7 theta)=(sin3 theta)/(sin5 theta)

    Prove that :(sin theta+2sin3 theta+sin5 theta)/(sin3 theta+2sin5 theta+sin7 theta)=(sin3 theta)/(sin5 theta)

    [[ Simplify :cos thetacos theta,sin theta-sin theta,cos theta]]+sin theta[[sin theta,-cos thetacos theta,sin theta]]

    sin^4theta+2sin^2thetacos^2theta=1-cos^4 theta

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