An inductor coil is connected to a capacitor and an AC source of rms voltage 8V in series. The rms current in the circuit is 16 A and is in phase with emf. If this inductor coil is connected to 6 V DC battery, the magnitude of steady current is

Options

A. `8 A`
B. `10 A`
C. `12 A`
D. `16 A`

Answer

C

Explanation

Given,
rms voltage of AC source `V_(rms)=8V` and the rms current in the circuit, `I_(rms)=16 A`
Accoding to the question,

`:.` Impedance of the circuit,
`Z=V_(rms)/I_(rms)=8/16`
`Z=0.5 Omega`
When the inductor coil is connected to a 6V DC
battery then `V_(rms)'=6V=V_(DC)`
`:.` Magnitude of steady current,
`I'=(V_(rms)')/Z=6/0.5=12 A`