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If OA = hati +2hatj+3 hatk and OB = 4 ha...

If `OA = hati +2hatj+3 hatk and OB = 4 hati +hatk` are the position vectors of the points A and B then , the position vector of a point on the line passing through B and parallel to the vector `OA xx OB` which is at a distance of `sqrt(189)` units from B is

A

`6 hati +11 hatj - 7 hatk`

B

`4 hati +11 hatj -8 hatk`

C

`2 hati-11 hatj +8 hatk`

D

`-2 hati -11 hatj +8 hatk`

Text Solution

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The correct Answer is:
A
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