An ideal gas is placed in a tank at `27^@C`.
The pressure is initially 600 kPa. One fourth of the gas is then released from tha tank and thermal equilibrium is established. What will be the pressure if the temperature is `327^@C` ?

Options

A. 900 kPa
B. 1000 kPa
C. 1050 kPa
D. 1250 kPa

Answer

A

Explanation

As, know that the ideal gas equation is given as, pV = nRT
It can be written as
`(p_1V_1)/(n_1T_1)=(p_2V_2)/(n_2T_2)`…….(i) (`because` R = constant)
Given `T_1 = 273 + 27^@ = 300 K and p_1 = 600 K Pa`
If one fourth of gas released from tank ,
then `n_2 =3/4 n_1 and V_2 =V_1` (`because` No change)
Given , `T_2 = 327 +273= 600 K`
So, from Eq. (i) we get
(600 V_1)/(n_1 300) = (p_2V_1)/(3/4 n_1 600) rArr p_2 = 900 K Pa`