The ratio of the height above the surface of earth to the depth below, the surface of earth, for gravitational accelerations to be the same (assuming small heights) is 

Options

A. `0.25`
B. `0.5`
C. `1.0`
D. `1.25`

Answer

B

Explanation

Gravitation at height h from surface,
`g_(h)=g(1-(2h)/( R ))`
Gravitation at depth d from surface,
`g_(d)=g(1-d//R)`
For `" "g_(h)=g_(d)`
`implies" "d=2h`
So, ratio of height w.r.t. depth is
`(h)/(d)=(1)/(2)=0.5`