For a reaction `2A_((g)) hArr 2B_((g))+ C_((g)), K_e=3.75xx10^(-1)` at 1069 K. The approximate value of `K_(p)` for this reaction at the same temperature is `(R=0.082 L "bar mol"^(-1) K^(-1))`

Options

A. `2.4xx10^(-4)`
B. `3.3xx10^(-4)`
C. `33xx10^(2)`
D. `7.2xx10^(4)`

Answer

B

Explanation

`K_(p)` is related to `K_(C)` by the formula.
`K_(p)=K_(C)(RT)^(Delta n)`
For the equation `2A(g) iff 2B(g)+C(g)`
`Deltan=(2+1)-2=1`
`R=0.0821" bar mol"^(-1)K^(-1)`
`T=1069" K"`
`K_(C)=375xx10^(-6)`
Substituting the values in equation and solving we get `K_(p)=3.3xx10^(-4)`