The degree of dissociation of `0.1 N CH_3 COOH` is (given `K_a=1xx10^(-5)`) approximately

Options

A. `1xx10^(-6)`
B. `1xx10^(-7)`
C. `1xx10^(-3)`
D. `1xx10^(-2)`

Answer

D

Explanation

The reaction equation of dissociation of `CH_(3)COOH` is
`CH_(3)COOH(aq)toCH_(3)COO^(-)+H^(+)`
`K_(a)=([CH_(3)COO]^(-)[H]^(+))/([CH_(3)COOH])=1.0xx10^(-5)`
When `N=1," "K_(a)=1.0xx10^(-5)`
When `N=0.1,K_(a)=(1xx10^(-5))/(0.1xx10^(-2))`
`implies" "K_(a)=10^(-2)`