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If the equations of the perpendicular bisectors of the sides AB and AC of a `Delta` ABC are x - y + 5 = 0 and x + 2y =0 respectively and if A is (1,-2), then the equation of the perpendicular bisector of the side BC is

A

3x + 3y + 5 = 0

B

9x - 23y + 40 =0

C

6x + 15y = 5

D

23x - 14y + 100 = 0

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D
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