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int cosec^5 x dx =...

`int cosec^5 x dx = `

A

`(cosec x cot^3 x )/(4) - 5/8 cosec x cot x + 3/8 log | tan x/2 | + c `

B

`- (cosec x cot^3 x )/(4) - 5/8 cosec x cot x + 3/8 log | tan x/2 | + c `

C

` - (cosecc^3 x cot x )/(4) - 3/8 cosec x cotx + 3/8 log | tan x/2 | + c`

D

`- (cosec^3 x cot x )/(4) + 3/8 cosec x cotx - 3/8 log | tan x/2 | + c `

Text Solution

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The correct Answer is:
C
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