Match the following :

The correct answer is

Options

A. `{:(A,B,C,D),(V,I,III,II):}`
B. `{:(A,B,C,D),(V,II,I,IV):}`
C. `{:(A,B,C,D),(III,V,I,IV):}`
D. `{:(A,B,C,D),(III,IV,I,II):}`

Answer

D

Explanation

(A) Trigonal planer ` to (III) BF_(3)` , because boron has three (3) valence electrons which are involved in formation of three sigma `(sigma)` bonds with 3F-atoms and has no lone pair (lp) of electrons.
B) Tetrahedral ` to (IV) C Cl_(4)` , because carbon has four (4) valnece electrons which are involved in formation of four sigma` (sigma)` bonds with 4Cl-atoms and has no lp of electrons.
(C) Trigonal bipyramidal ` to (I) PCl_(5)` , because phosphorus has five valence electrons which are involved in formantion of fice sigma `(sigma)` bond with 5Cl atoms and has no lp of electrons .
(D) Octahedral ` to(II) SF_(6)` , because sulphur has six valence electrons which are involved in formation of six sigma `(sigma)` bonds with 6F-atoms ans has no lp of electrons.
Hence , option (d) is the correct answer .