Which of the following statements is correct in the Kolbe's electrolysis?

Options

A. Hydrcoarbons containing even number of carbon atoms produced at anonde
B. Hydrocarbons containing odd number of carbon atoms produced at anode
C. Hydrocarbons containing even number of carbon atoms produced at cathode
D. Hydrocarbons containing odd number of carbon atoms produced at cathode

Answer

A

Explanation

During Kolbe's electrolysis hydrocarbons with even number of C-atoms are because Kolbe's electrolysis occurs as follows:
at anode
`2RCOO^(-) Na ^(+) overset("Electrolysis")hArr underset ("Alkene at anode")(R-R + 2CO_(2)(g))`
At cathode
`H_(2) P + 2e^(-) to 2OH^(-)+ 2H^(@)`
` 2H^(@) to H_(2)(g)`
For example ,
In case of alkenes
`underset(CH_(2) - COOK)overset(CH_(2)- COOK)" | " + 2H_(2)O overset"(Electrolysis)" (to)overset(CH_(2))underset("At anode")underset(CH_(2))(||)+ 2CO_(2) (g)`
In case of alkynes
`underset(CH_(2) - COOK)overset(CH_(2)- COOK)" || " + 2H_(2)O overset"(Electrolysis)" (to)overset(CH_(2))underset("At anode")underset(CH_(2))(|||)+ 2CO_(2) `
As hydrocarbons are obtained by Kolbe's electrolysis via combination of two alkyl groups (i.e. R-R) . Thus , it always give hydrocarbons in which C-atoms are present in even number at anode . Hence ,option (a) is the correct answer .