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In triangle ABC, D is mid point of BC, i...

In triangle ABC, D is mid point of BC, if 'AD' is perpendicular to 'AC then `cos A cos C`

A

`1/3(1 c ^(2) + a ^(2))/(ab)`

B

`(2 (c ^(2) + a ^(2)))/(ab)`

C

`(2 (c ^(2) -a ^(2)))/(3ac)`

D

`(3 (a ^(2) + b ^(2)))/(2bc)`

Text Solution

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The correct Answer is:
C
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