Dimension of the quantity `(p)/(epsi _(0) mu_(0)),` where p is the pressure, `epsi _(0)` is electric permitivity of face space and `mu _(0)` is permebility of free space, will be

Options

A. `[MLT ^(-4)]`
B. `[ML^(2)T^(-2)]`
C. `[ML^(3) T^(-3)]`
D. `[ML^(2) T ^(-4)]`

Answer

A

Explanation

Given, quantity `= (p )/(epsi_(0) mu_(0)),`
where , p = pressure,
`epsi_(0)=` permittivity of free space and `mu_(0)=` permeability of free space.
We known that, speed of light , `c = (1)/(sqrt(epsi _(0) mu_(0)))or c ^(2) = (1)/(epsi _(0) mu_(0))`
Now dimension of `pc ^(2) =[ML^(-1)T^(-2)] [LT^(-1)]^(2)=[MLT^(-4)]`