A `1.5` kg ball is shot upward at an angle of `34^(@)` to the horizontal with an initial speed of `2m m//s,` then maximum height of the ball reaches is (use `cos 34^(@)=0.83 or sin 34^(@)=0.56)`

Options

A. `6.3m`
B. `9.4m`
C. `13.8m`
D. `11.2m`

Answer

A

Explanation

Given, initial speeed, `u = 20 m//s`
angle of projection, `theta = 34^(@)`
Maximum height , `H = ( u ^(2) sin ^(2) theta)/(2g)`
`r = ((20) ^(2) xx sin %(2) 34)/(2xx9.8) = (400xx(0.56) ^(2))/(2xx 9.8)`
`H = (125. 44)/(19.6)=6.3 m`