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The equation of the circle passing throu...

The equation of the circle passing through (1,2) and the points of intersection of the circles `x^2+y^2-8x-6y+21=0` and `x^2+y^2-2x-15=0` is

A

`x^(2)+y^(2)+6x-2y+9=0`

B

`x^(2)+y^(2)-6x-2y+9=0`

C

`x^(2)+y^(2)-6x-4y+9=0`

D

`x^(2)+y^(2)-6x+4y+9=0`

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Find the equation of the circle passing therough the points of intersection of the circles. x^2 + y^2 - 8x - 6y + 21 = 0 "__"(1) x^2 + y^2 - 2x -15 = 0 "___"(2) and (1, 2).

Find the equation of the circle passing through the points of intersection of the circles x^(2)+y^(2)-8x-6y-21=0 x^(2)+y^(2)-2x-15=0and(1,2)

Show that the locus of the centres of the circles passing through the points of intersections of the circles x^2+y^2=1 and x^2+y^2-2x+y=0 is x+2y=0

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The locus of the centres of the circles passing thorugh the points of intersection of the circles x^(2) + y^(2) =1 and x^(2) + y^(2) - 2x +y=0 is

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