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A thermos flask contains 250 g coffee at...

A thermos flask contains 250 g coffee at `90^(@)C`. To this 20 g of milk at `5^(@)C` is added. After equilibrium is established, the temperature of the liquid is
(Assume no heat loss to the thermos bottle . Take specific heat of coffee and milk as `1.00 cal//g^@C`)

A

`3.23^(@)C`

B

`3.15^(@)C`

C

`83.7^(@)C`

D

`37.8^(@)C`

Text Solution

Verified by Experts

Let after getting equlibrium stage final temperature is T.
Then, according to loss of calorimetry
Heat loss = Heat gain
`rArr(250)(1)(90-T)=20(1)(T-5)`
`rArr " " T=83.7^(@)C`
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