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The displacement of a particle moving in...

The displacement of a particle moving in a straight line is given by the expression `x=At^(3)+Bt^(2)+Ct+D` in metres, where t is in seconds and A,B,C and D are constant. The ratio between the initial acceleration and initial velocity is

A

`(2C)/(B)`

B

`(2B)/( C)`

C

2C

D

`( C)/(2B)`

Text Solution

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Displacement of a particle moving in a straight line `(x) = At^(3) + Bt^(2) + Ct + D`
`therefore "Velocity", " " v = (dx)/(dt) = 3At^(2) + 2Bt + C`
`V_("intial") = C`
and `a = (d^(2)X)/(dt^(2))` = 6At + 2B`
`a_(intial) = 2B`
`therefore` Ratio between intial acceleration and intial velocity is `(2B)/( C)`.
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