A, B, C are points in a vertical line such that AB = BC. If a body falls freely from rest at A and `t_(1)` and `t_(2)` are times taken to travel distances AB and BC, then ratio `(t_(2)//t_(1))` is

Options

A. `sqrt(2)+1`
B. `sqrt(2)-1
C. `2sqrt(2)`
D. `(1)/(sqrt(2)+1)`

Explanation

If a body falls freely from rest at A. Then, time taken to travel from A to B (time taken)
`t_(1) = sqrt((2h)/(8))`
Time taken to travel from B to C
(time taken) `t_(2) = sqrt((4h)/(8)) - sqrt((2h)/(8))`
`therefore " " (t_(2))/(t_(1)) = sqrt(2) - 1`