A body of mass 2.4 kg is subjected to a force which with distance as shown in figure. The starts from rest aat x = 0. Its velocity at x = 9 m is

Options

A. `5sqrt(3)m//s`
B. `20sqrt(3)m//s`
C. 10 m/s
D. 40 m/s

Explanation

Work done in a moving body is get converted into kinetic energy.

`therefore " " int Fdx = (1)/(2) m(v^(2) - 0^(2))`
`rArr " " (1)/(2) (9+3)(20) = (1)/(2) (2.4)v^(2)`
`rArr " " v = 10 m//s`