What is the weight (in g) of `Na_(2) CO_(3)` (molar mass= 106) present in 250 mL of its 0.2 M solution?

Options

A. 0.53
B. 5.3
C. 1.06
D. 10.6

Explanation

Molarity
`=("Weight of solute")/("Molecular weight of solute")xx(1000)/("volume"("in"mL))`
`0.2=("Weight of solute")/(106)xx(1000)/(250)`
`therefore " " "Weight of solute" = (0.2 xx 106xx250)/(1000)=5.3gm`