An aqueous dilute solution containing non-volatile solute boils at `100.052^(@)C`. What is the molality of solution? (`K_(b) - 0.52 kg.mol^(-1)K`, boiling temperature of water = `100^(@)C`)

Options

A. 0.1 m
B. 0.01 m
C. 0.001 m
D. 1.0 m

Explanation

`DeltaT_(b)=K_(b).m`
`DeltaT_(b)=K_(b).m`
where, `K_(b)` = molal elevation constant
m = molality
(100.052 - 100.00) = (0.52) (m)
`0.052 = 0.52 xx m`
m = 0.1