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Given N(2)(g)+3H(2)(g)to2NH(3)(g),Delta(...

Given `N_(2)(g)+3H_(2)(g)to2NH_(3)(g),Delta_(r)H^(theta)=-92.4 kJ mol^(-1)` What is the standard enthalpy of formation of `NH_(3)` gas ?

A

`-92`

B

`+46`

C

`+92`

D

`-62`

Text Solution

Verified by Experts

The correct Answer is:
d
Given,
`N_(2) (g) + 3H_(2) (g) to 2NH_(3) (g), Delta_(r ) H^(@) = - 92 kJ`
Chemical reaction for enthalpy of formation of `NH_(3)`
`(1)/(2) N_(2) (g) + (3)/(2) (g) to NH_(3) (g)`
`(:' H_(f)^(@) "for" N_(2) "and" h_(2) = 0)`
Therefore,, `Delta_(f) H^(@) = (-Delta_(f) h^(@))/(2) = (-92)/(2)`
= - 46 kJ `"mol"^(-1)`
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