The hybridisation of each carbon in the following compound respectively is
`CH_(3)- overset(O)overset(||)(C ) - CH_(2) - CN`

Options

A. `sp^(3),sp^(2),sp^(3),sp`
B. `sp^(3),sp^(3),sp^(2),sp`
C. `sp^(3),sp,sp^(3,sp^(2)`
D. `sp^(3),sp^(2),sp,sp^(3)`

Answer

a

Explanation

In the compound,

The C-atoms that is bonded to four different atoms involve four orbitals (1 of s and 3 of p - orbitals )
hybridisation. Hence, they have `sp^(3)` hybridisation as in cases of (i) and (ii).
The C-atom bonded to three different atoms involves three orbitals (1 of s and 2 of p -orbitals). Hence, the `sp^(2)` hybridisation in case of (ii)
The c-atoms bonded to two different atoms involves two orbitals (1 of s and 1 of p orbitals). Hence, the sp. hybridisation in case of (M).