The molality of an aqueous dilute solution containing non-volatile solute is 0.1 m. What is the boiling temperature (in `.^(@)C`) of solution? (Boiling point elevation constant, `k_(b) = 0.52 kg mol^(-1) K` boiling temperature of water `= 100 .^(@)C`)

Options

A. 100.0052
B. 100.052
C. 100
D. 100.52

Answer

b

Explanation

Given, `K_(0) = 0.52 kg mol^(-3) K`
Boiling point of water `= 100^(@)C`
`m = (Delta T_(b))/(K_(b))`
`0.1 = (Delta T_(b))/(0.52)`
`Delta T_(b) = 0.052`
Boiling point of solution `(T_(b)) = 100 + Delta T_(b)`
= 100 + 0.052 = 100.052`