For the reaction
`5 Br(aq) + BrO_(3)^(-)(aq) + 6H^(+)(aq) to 3 Br_(3)(aq) + 3H_(2)O(l)`
If, ` -(Delta[Br])/(Deltat) = 0.05 mol L ^(-1)mi n^(-1) , -(Delta[BrO_(3)])/(Deltat) in mol L ^(-1)mi n^(-1) is`

Options

A. 0.01
B. 0.3
C. 0.03
D. 0.005

Answer

c

Explanation

`5Br^(-) (aq) + 6H^(+) (aq) + BrO_(3)^(-) (aq) to 3 Br_(2) (aq) + 3H_(2) O (I)`
since, we've `- (1)/(5) (Delta [Br^(-)])/(Delta T) = - (Delta[BrO_(3)^(-)])/(Delta t) = + (1)/(3) (Delta [Br_(2)])/(Delta t)`
`:. (Delta BrO_(3)^(-))/(Delta t) = (1)/(3) (Delta[Br_(2)])/(Delta t)`
`implies (Delta [Br_(2)])/(Delta t) = 3 (Delta[BrO_(3)^(-)])/(Delta t) = 3 xx 0.01 = 0.03`