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Xenon reacts with fluorine at 873 K and ...

Xenon reacts with fluorine at 873 K and 7 bar to form `XeF_(4)`. In this reaction, the ratio of xenon and fluorine required is

A

`1 : 5`

B

`10 : 1`

C

1 : 3`

D

` 5 : 1`

Text Solution

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The correct Answer is:
a
`XeF_(4)` is obtained by heating a mixture of xenon and fluronie in the molar ratio of 1 : 5 at 873 K and 7 bar pressure in an enclosed nickel vessel for a few hours. The reaction proceeds as
`Xe(g) + 2F_(2)(g) underset(7 bar)/(873 K)(to) XeF_(4)`
The extra fluorine taken, increases the production.
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