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For theta in (0, (pi)/(2)) "sech"^(-1) (...

For `theta in (0, (pi)/(2)) "sech"^(-1) (cos theta)` is equal to

A

`log|tan ((x)/(6) + (theta)/(2))|`

B

`log|tan ((pi)/(3) + (theta)/(2))|`

C

`log|tan ((pi)/(4) + (theta)/(2))|`

D

`log|tan((pi)/(4) - (theta)/(2))|`

Text Solution

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The correct Answer is:
c
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