A simple pendulum of length 1 m is freely suspended from the ceiling of an elevator the time period of small oscollations as the elevator moves up with an acceleration of `2m//s ^2 ` is ( use ` g=10 m//s ^2)`

Options

A. `(pi)/(sqrt(5))s`
B. `sqrt(2/5) pi s `
C. `(pi) /( sqrt2)s`
D. `(pi) /(sqrt3)s`

Answer

D

Explanation

Given ,
Length of simple pendulum (L ) =1 m
Acceleration `(a) = 2 m//s ^2`
Graviation acceleration `(g) = 10 m//s^2`
We know that
` T = 2pi sqrt((1)/(g+a )) = 2pi sqrt((1)/(10+2))`
`=2pi sqrt((1)/(12))= pi sqrt((4)/(12))`
` I= (pi)/(sqrt(3))s`