A beam of light propagation at an angle ` alpha _1 ` from a medium 1 through to another medium 2 at an angle ` alpha_2` if the wavelength of light in medium 1 is ` lamda _1 ` , then the wavelength of light in medium 2, `( lamda _2)` is

Options

A. `( sin alpha _2)/( sin alpha _1) lamda_1`
B. `( sin alpha _1)/( sin alpha _2) lamda_2`
C. `((alpha _1)/( alpha _2))lamda_1`
D. `lamda _1`

Answer

A

Explanation

WE know that ,
` lamda = ( lamda _0) /( mu ) `
According to the question ,
` ( sin alpha _1 ) /( sin alpha _2) = ( mu _2) /( mu _1) = ( lamda _1) /( lamda _2)`
` lamda _2 = lamda _1 ( sin alpha _2 ) /( sin alpha _1)`