A particle of mass M is moving in a horizontal circle of radius R with uniform speed v. When the particle moves from one point to a diametrically opposite point , its

Options

A. momentum does not change
B. momentum changes by 2 Mv
C. Kinetic energy changes by ` ( Mv^2)/(4)`
D. Kinetic energy changes by ` Mv^2`

Answer

B

Explanation

Given , velocity of particle = V
change in momentum = final momentum - initial momentum ` = Mv -(- Mv ) = 2 Mv `