AD is a medium of DeltaABC and P is a po...

AD is a medium of `DeltaABC` and P is a point on the side AC of `DeltaABC` such that area of `DeltaADP` : area of `DeltaABD` = 2 : 3, Determine the ratio (area of `DeltaPDC` : area of `DeltaABC`).

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CALCUTTA BOOK HOUSE-THEOREMS ON AREAS-EXERCISE-3

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