Form a quadratic equation in one variable from the following statement(s) :
The product of two consecutive positive odd numbers is 143.

Explanation

Let n be any natural number.
Then (2n+1) is an odd positive number. We know that the difference between two consecutive odd positive numbers is always 2.
`:.` the next or the previous odd positive number of (2n+1) is
`(2n+1-2)=2n-1or,(2n+1+2)=2n+3`
As per question, `(2n-1)(2n+1)=143or,(2n+1)(2n+3)=143`
or, `(2n)^(2)-(1)^(2)=143or,4n^(2)+2n+6n+3=143`
or, `4n^(2)-1=143or,4n^(2)+8n=143-3`
or, `4n^(2)-144=0or,4n^(2)+8n-140=0`
or, `n^(2)-36=0or,n^(2)+2n-35=0`
Hence, the required quadratic equations are `n^(2)-36=0andn^(2)+2n-35=0`.