One root of the quadratic equation `x^(2)-sqrt3x-6=0` is

Options

A. `4sqrt3`
B. `sqrt3`
C. `2sqrt3`
D. `-2sqrt3`

Explanation

We have, `x^(2)-sqrt3x-6=0`
or, `x^(2)-(2sqrt3-sqrt3)x-6=0`
or, `x^(2)-2sqrt3x+sqrt3x-6=0`
or, `x(x-2sqrt3)+sqrt3(x-2sqrt3))=0`
or, `(x-2sqrt3)(x+sqrt3)=0`
`:.` either `(x-2sqrt3)=0or,(x+sqrt3)=0`
`impliesx=2sqrt3" "impliesx=-sqrt3`
`:.2sqrt3` is root of the given equation.
`:.` c is correct.