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The tens' digit of a two digit number is...

The tens' digit of a two digit number is less by 3 than unit digit. If the product of the two digits is subtracted from the number the result is 15. Find the unit digit of the number.

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Let the unit digit be x.
`:.` The tens' digit is (x-3)
`:.` the number =10(x-3)+x.
`=10x-30+x=11x-30`.
As per questions, `(11x-30)-x(x-3)=15`.
or, `11x-30-x^(2)+3x=15or,x^(2)-14x+45=0`
or, `x^(2)-(5+9)x+45=0`
or, `x^(2)-5x-9x+45=0`
or, `x(x-5)-9(x-5)=0`
or, `(x-5)(x-9)=0`.
`:.` either `x-5=0" "or,x-9=0`
`impliesx=5" "or,xx=9`.
Hence the unit digit is 5 or 9
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CALCUTTA BOOK HOUSE-QUADRATIC EQUATION IN ONE VARIABLE-EXERCISE-1.5
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