Solve the following equations using Sreedhar Acharya's formula :
`10x^(2)-x-3=0`

Explanation

Given that `10x^(2)-x-2-3=0.......(1)`
Comparing (1) with `ax^(2)+bx+c=0` we get, `a=10,b=-1andc=-3`.
`:.` by Sreedhar Acharya's formula we get, `x=(-(1)pmsqrt((-1)^(2)-4xx10xx(-3)))/(2xx10)`
`=(1pmsqrt121)/(20)=(1pm11)/(20)`
`=(1+11)/(20)` (taking +sign) and `=(1-11)/(20)` (taking -sign)
`=(12)/(20)and(-10)/(20)`
`=(3)/(5)and-(1)/(2)`
Hence the solutions are `x=(3)/(5)andx-(1)/(2)`