[" 11."(ax)/(b)-(by)/(a)=a+b],[ax-by=2ab" ."[CBSE" 2007"C]]

Solve the following equations: (ax)/(b)-(by)/(a)=a+b , ax-by=2ab.

Solve the following system of equations by method of cross-multiplication: (ax)/(b)-(by)/(a)=a+b,quad ax-by=2ab

int (2ax+b)/(sqrt(ax^2+bx+c))dx

intsec^2(ax+b)=(tan(ax+b))/a +c,a ne0

int (ax+b)/(ax^2+2bx+c) dx

intsin(ax+b) dx = -(cos(ax+b))/a + c, a ne 0

intsec(ax+b) tan (ax+b)dx=(sec(ax+b))/a + c, a ne0

If |{:(a,b,ax+by),(b,c,bx+cy),(ax+by,bx+cy,0):}|=0 and ax^2+2abxy+cy^2ne0," then "......

If x^(2)+px+1 is a factor of ax^(3)+bx+c then a a^(2)+c^(2)=-ab b) a^(2)+c^(2)ab c) a^(2)-c^(2)=ab d a^(2)-c^(2)=-ab